Question

3(х-4)=51; 5(х+3)=30

Answer 1

Ответ:

3(х-4)=51

3х-12=51

3х=63

х=63/3=21

_________________

3(21-4)=51

3*17=51

51=51

5(х+3)=30

5х+15=30

5х=15

х=15/5=3

__________________

5(3+3)=30

5*6=30

30=30

Пошаговое объяснение:

Answer 2

Ответ:

Пошаговое объяснение:

3(х - 4) = 51

3х - 12 = 51

3х = 51 + 12

3х = 63

х = 63 : 3

х = 21

5(х + 3) = 30

5х + 15 = 30

5х = 30 - 15

5х = 15

х = 15 : 5

х = 3

Answer 3

To solve the equations, let's start with the first one:

1. 3(x - 4) = 51

First, distribute the 3 on the left side of the equation:

3x - 12 = 51

Now, add 12 to both sides to isolate the variable:

3x - 12 + 12 = 51 + 12 3x = 63

Next, divide both sides by 3 to solve for x:

3x / 3 = 63 / 3 x = 21

So, the solution to the first equation is x = 21.

Now, let's move on to the second equation:

2. 5(x + 3) = 30

First, distribute the 5 on the left side of the equation:

5x + 15 = 30

Now, subtract 15 from both sides to isolate the variable:

5x + 15 - 15 = 30 - 15 5x = 15

Finally, divide both sides by 5 to solve for x:

5x / 5 = 15 / 5 x = 3

So, the solution to the second equation is x = 3.

To summarize:

1. For the first equation, x = 21.
2. For the second equation, x = 3.