Question

4)144:(x-3)=366)(x+67):18=42)28*(x+5)=224​

Answer 1

( 2 )

$28*(x+5)=224\\\\x+5=224:28\\\\x+5=8\\\\x=8-5\\\\x=3$

Проверка:

$x=3\\\\28*(3+5)=224\\\\28*8=224\\\\224=224$

( 4 )

$144:(x-3)=36\\\\x-3=144:36\\\\x-3=4\\\\x=4+3\\\\x=7$

Проверка:

$x=7\\\\144:(7-3)=36\\\\144:4=36\\\\36=36$

( 6 )

$(x+67):18=4\\\\x+67=4*18\\\\x+67=72\\\\x=72-67\\\\x=5$

Проверка:

$x=5\\\\(5+67):18=4\\\\72:18=4\\\\4=4$

Answer 2

To solve each of these equations, you need to isolate the variable 'x'. Let's work on each one step by step:

1. $144:(x-3) = 366$

   To solve for 'x', first, multiply both sides of the equation by (x-3) to get rid of the denominator:

   $144 = 366(x-3)$

   Now, divide both sides by 366:

   $x - 3 = \frac{144}{366}$

   $x - 3 = \frac{24}{61}$

   Add 3 to both sides to isolate 'x':

   $x = \frac{24}{61} + 3$

   $x = \frac{24}{61} + \frac{183}{61}$

   $x = \frac{24 + 183}{61}$

   $x = \frac{207}{61}$

2. $\frac{366(x+67)}{18} = 42$

   To solve for 'x', first, multiply both sides of the equation by 18 to get rid of the fraction:

   $366(x+67) = 42 \cdot 18$

   $366(x+67) = 756$

   Now, divide both sides by 366:

   $x + 67 = \frac{756}{366}$

   $x + 67 = \frac{126}{61}$

   Subtract 67 from both sides to isolate 'x':

   $x = \frac{126}{61} - 67$

   $x = \frac{126}{61} - \frac{67 \cdot 61}{61}$

   $x = \frac{126 - 67 \cdot 61}{61}$

   $x = \frac{126 - 4087}{61}$

   $x = \frac{-3961}{61}$

3. $28(x+5) = 224$

   To solve for 'x', first, divide both sides of the equation by 28:

   $x + 5 = \frac{224}{28}$

   $x + 5 = 8$

   Subtract 5 from both sides to isolate 'x':

   $x = 8 - 5$

   $x = 3$

So, the solutions for the equations are:

1. $x = \frac{207}{61}$

2. $x = \frac{-3961}{61}$

3. (x = 3)