Question

Петя выписал на доску все положительные числа, на которые делится некоторое натуральное число N. Оказалось, что сумма двух наибольших выписанных чисел равна 3021. Найдите все такие N. Если чисел несколько, в ответ запишите их сумму. 15 баллов дам

Answer 1

Ответ: вроде бы 4703 возможно ошибка

Пошаговое объяснение: тоже сириус делаешь?

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Answer 2

To find all the natural numbers N that satisfy the given condition, we need to consider the positive numbers that divide N and find the sum of the two largest numbers among them.

Let's break down the problem step by step:

Step 1: Finding the Divisors of N

We need to find all the positive divisors of N. These are the numbers that divide N without leaving a remainder. To find the divisors, we can iterate through all the numbers from 1 to N and check if they divide N evenly.

Step 2: Finding the Two Largest Divisors

Once we have the list of divisors, we need to find the two largest numbers among them. We can sort the list of divisors in descending order and select the first two numbers.

Step 3: Checking the Sum

We need to check if the sum of the two largest divisors is equal to 3021. If it is, then N satisfies the given condition.

Now, let's apply these steps to find all the values of N that satisfy the condition.

Example Calculation:

Let's consider an example to illustrate the steps. Suppose we have N = 12.

Step 1: Finding the Divisors of 12 The divisors of 12 are 1, 2, 3, 4, 6, and 12.

Step 2: Finding the Two Largest Divisors Sorting the divisors in descending order, we get [12, 6, 4, 3, 2, 1]. The two largest divisors are 12 and 6.

Step 3: Checking the Sum The sum of the two largest divisors is 12 + 6 = 18, which is not equal to 3021.

Therefore, N = 12 does not satisfy the given condition.

Finding All Values of N

To find all the values of N that satisfy the condition, we can iterate through all the natural numbers and apply the steps mentioned above. We can keep track of the values of N that satisfy the condition and calculate their sum.

Let's perform the calculations to find the values of N:

N = 1: The divisors of 1 are [1]. The sum of the two largest divisors is 1, which is not equal to 3021.

N = 2: The divisors of 2 are [1, 2]. The sum of the two largest divisors is 2 + 1 = 3, which is not equal to 3021.

N = 3: The divisors of 3 are [1, 3]. The sum of the two largest divisors is 3 + 1 = 4, which is not equal to 3021.

N = 4: The divisors of 4 are [1, 2, 4]. The sum of the two largest divisors is 4 + 2 = 6, which is not equal to 3021.

N = 5: The divisors of 5 are [1, 5]. The sum of the two largest divisors is 5 + 1 = 6, which is not equal to 3021.

N = 6: The divisors of 6 are [1, 2, 3, 6]. The sum of the two largest divisors is 6 + 3 = 9, which is not equal to 3021.

N = 7: The divisors of 7 are [1, 7]. The sum of the two largest divisors is 7 + 1 = 8, which is not equal to 3021.

N = 8: The divisors of 8 are [1, 2, 4, 8]. The sum of the two largest divisors is 8 + 4 = 12, which is not equal to 3021.

N = 9: The divisors of 9 are [1, 3, 9]. The sum of the two largest divisors is 9 + 3 = 12, which is not equal to 3021.

N = 10: The divisors of 10 are [1, 2, 5, 10]. The sum of the two largest divisors is 10 + 5 = 15, which is not equal to 3021.

N = 11: The divisors of 11 are [1, 11]. The sum of the two largest divisors is 11 + 1 = 12, which is not equal to 3021.

N = 12: The divisors of 12 are [1, 2, 3, 4, 6, 12]. The sum of the two largest divisors is 12 + 6 = 18, which is not equal to 3021.

N = 13: The divisors of 13 are [1, 13]. The sum of the two largest divisors is 13 + 1 = 14, which is not equal to 3021.

N = 14: The divisors of 14 are [1, 2, 7, 14]. The sum of the two largest divisors is 14 + 7 = 21, which is not equal to 3021.

N = 15: The divisors of 15 are [1, 3, 5, 15]. The sum of the two largest divisors is 15 + 5 = 20, which is not equal to 3021.

N = 16: The divisors of 16 are [1, 2, 4, 8, 16]. The sum of the two largest divisors is 16 + 8 = 24, which is not equal to 3021.

N = 17: The divisors of 17 are [1, 17]. The sum of the two largest divisors is 17 + 1 = 18, which is not equal to 3021.

N = 18: The divisors of 18 are [1, 2, 3, 6, 9, 18]. The sum of the two largest divisors is 18 + 9 = 27, which is not equal to 3021.

N = 19: The divisors of 19 are [1, 19]. The sum of the two largest divisors is 19 + 1 = 20, which is not equal to 3021.

N = 20: The divisors of 20 are [1, 2, 4, 5, 10, 20]. The sum of the two largest divisors is 20 + 10 = 30, which is not equal to 3021.

N = 21: The divisors of 21 are [1, 3, 7, 21]. The sum of the two largest divisors is 21 + 7 = 28, which is not equal to 3021.

N = 22: The divisors of 22 are [1, 2, 11, 22]. The sum of the two largest divisors is 22 + 11 = 33, which is not equal to 3021.

N = 23: The divisors of 23 are [1, 23]. The sum of the two largest divisors is 23 + 1 = 24, which is not equal to 3021.

N = 24: The divisors of 24 are [1, 2, 3, 4, 6, 8, 12, 24]. The sum of the two largest divisors is 24 + 12 = 36, which is not equal to 3021.

N = 25: The divisors of 25 are [1, 5, 25]. The sum of the two largest divisors is 25 + 5 = 30, which is not equal to 3021.

N = 26: The divisors of 26 are [1, 2, 13, 26]. The sum of the two largest divisors is 26 + 13 = 39, which is not equal to 3021.

N = 27: The divisors of 27 are [1, 3, 9, 27]. The sum of the two largest divisors is 27 + 9 = 36, which is not equal to 3021.

N = 28: The divisors of 28 are [1, 2, 4, 7, 14, 28]. The sum of the two largest divisors is 28 + 14 = 42, which is not equal to 3021.

N = 29: The divisors of 29 are [1, 29]. The sum of the two largest divisors is 29 + 1 = 30, which is not equal to 3021.

N = 30: The divisors of 30 are [1, 2, 3, 5, 6, 10, 15, 30]. The sum of the two largest divisors is 30 + 15 = 45, which is not equal to 3021.

N = 31: The divisors of 31 are [1, 31]. The sum of the two largest divisors is 31 + 1 = 32, which is not equal to 3021.

N = 32: The divisors of 32 are [1, 2, 4, 8, 16, 32]. The sum of the two largest divisors is 32 + 16 = 48, which is not equal to 3021.

N = 33: The divisors of