Question

-1.21x + 53xy² + 35xy², якщо x =1, y=0.1пожалуйста срочно нада!!!​

Answer 1

Ответ:

якщо а=1 у=0.1, то -1.21x + 53xy² + 35xy²=-1.21+88*0.1*0.1=-0.33

Пошаговое объяснение:

Answer 2

Ответ:

x =1, y=0.1

$-1,21x+53xy^{2} +35xy^{2} = -1,21* 1+53*1*(0,1)^{2} +35*1*(0,1)^{2} =-1,21+53*0,01+35*0,01=-1,21+0,53+0,35=-1,21+0,88=-0,33$

Answer 3

To find the value of the expression -1.21x + 53xy² + 35xy² when x = 1 and y = 0.1, we can substitute the given values into the expression and simplify.

Let's start by substituting x = 1 and y = 0.1 into the expression:

-1.21(1) + 53(1)(0.1)² + 35(1)(0.1)²

Simplifying the expression further:

-1.21 + 53(0.01) + 35(0.01)

Now, let's calculate the values:

-1.21 + 0.53 + 0.35

Adding the values together:

-1.21 + 0.53 + 0.35 = -0.33

Therefore, when x = 1 and y = 0.1, the value of the expression -1.21x + 53xy² + 35xy² is -0.33.

Please note that the above calculation is based on the given expression and values.