Question

СРОЧНО любчик і ростик кожних 5 хв відпилюють від колоди брусок завдовжки 2м.за скільки хвилин на такі ж бруски буде розпиляної колоду завдовжки 10 м?​

Answer 1

Ответ:

25 хвилин.

Пошаговое объяснение:

5 хв = 2 м

х хв = 10 м

$x = \frac{10*5}{2} = 25$ хв

Answer 2

Ответ:

25 хвил

Пошаговое объяснение:

5 хв = 2 м

х хв = 10 м

x = \frac{10*5}{2} = 25x=

2

10∗5

=25 хв

Answer 3

According to Google Translate, your question in English is:

Answer in detail. URGENTLY love and rostik every 5 minutes saw off a log from a log 2m long. how many minutes will the log be sawn into the same bars 10m long?

To solve this math problem, we can use the following steps:

- Let x be the number of minutes it takes to saw the log into 10m long bars. - Since love and rostik saw off a 2m long bar every 5 minutes, the rate of sawing is 2/5 m/min. - The total length of the log is 10m, so the number of 2m long bars that can be made from it is 10/2 = 5. - The total time it takes to saw the log into 5 bars is x minutes, so the total length of the log that is sawed in x minutes is 2/5 * x m. - Since the total length of the log that is sawed in x minutes is equal to the total length of the log, we can write the equation:

2/5 * x = 10

- To solve for x, we can multiply both sides by 5/2 and get:

x = 10 * 5/2

- Simplifying, we get:

x = 25

- Therefore, it takes 25 minutes to saw the log into 10m long bars.