Question

Стрелок стреляет по мишени 4 раза. Вероятность попадания в мишень при одном выстреле равна 0,7. Найти вероятность того, что при четырёх выстрелах стрелок промахнётся хотя бы 1 раз. Решите пожалуйста!

Answer 1

Ответ:

0,76

Пошаговое объяснение:

Стрелок промахнется хотя бы 1 раз - противоположное событие : не промахнётся ни разу.

Вероятность этого события q=0,7⁴=0, 2401

Тогда искомая вероятность: p=1-q

p=1-0,2401≈0,76

Answer 2

Problem Analysis

We are given that a shooter takes 4 shots at a target, and the probability of hitting the target with a single shot is 0.7. We need to find the probability that the shooter will miss the target at least once in the 4 shots.

Solution

To find the probability that the shooter will miss the target at least once, we can calculate the probability of the complement event, which is the probability that the shooter will hit the target in all 4 shots, and then subtract it from 1.

The probability of hitting the target with a single shot is given as 0.7. Therefore, the probability of missing the target with a single shot is 1 - 0.7 = 0.3.

Since the shooter takes 4 shots, the probability of hitting the target in all 4 shots is (0.7)^4, and the probability of missing the target in all 4 shots is (0.3)^4.

To find the probability of missing the target at least once, we subtract the probability of hitting the target in all 4 shots from 1:

Probability of missing the target at least once = 1 - Probability of hitting the target in all 4 shots

Let's calculate this probability:

Probability of hitting the target in all 4 shots = (0.7)^4 = 0.2401

Probability of missing the target at least once = 1 - 0.2401 = 0.7599

Therefore, the probability that the shooter will miss the target at least once in the 4 shots is approximately 0.7599.

Answer

The probability that the shooter will miss the target at least once in the 4 shots is approximately 0.7599.