Question

через первую трубу водоём можно наполнить за 6 часов а вторую за 1цел. 1/3от времени первой за сколько они наполнятся за сколько часов наполнится водоём при совместной работе этих труб​

Answer 1

ОТВЕТ: 2 4/7 часа

Время, через которое, 2-я труба наполнит водоëм:

6÷11/3=6.3/4=(3-3)/2=9/24

За единицу примем сам водоём. Тогда:

1/6 - производительность 1-й трубы; 1/(9/2)=2/9 - производительность 2-й трубы.

Производительность двух труб:

1/6 +2/9=3/18 +4/18=7/18

Время, за которое наполнят две трубы водоём:

1/(7/18) 18/7= 2 4/7 ч

Answer 2

Solution:

To solve this problem, we can use the concept of work done by each pipe per hour. Let's denote the rate of filling the first pipe as R1 and the rate of filling the second pipe as R2.

Given: - Time taken to fill the first pipe = 6 hours - Time taken to fill the second pipe = 1 hour and 1/3 of an hour

We can calculate the rates of filling for each pipe using the formula:

Rate = Work / Time

For the first pipe: R1 = 1/6 (as it fills the reservoir in 6 hours)

For the second pipe: R2 = 1 / (1 + 1/3) = 1 / (4/3) = 3/4 (as it fills the reservoir in 1 hour and 1/3, which is 4/3 hours)

Now, to find out how long it takes for both pipes to fill the reservoir together, we can use the formula:

Time = 1 / (R1 + R2)

Let's calculate the time it takes for both pipes to fill the reservoir together.

Calculation:

R1 = 1/6 (rate of filling for the first pipe) R2 = 3/4 (rate of filling for the second pipe)

Time = 1 / (1/6 + 3/4) Time = 1 / (2/12 + 9/12) Time = 1 / (11/12) Time = 12/11 hours

So, when both pipes work together, they will fill the reservoir in 12/11 hours.

Therefore, when working together, the reservoir will be filled in 12/11 hours.

I hope this helps! If you have any further questions, feel free to ask.