Question

Длина прямоугольника 7 дм.это на 32 см больше чем ширина .найди пирометре и площадь этого прямо угольника

Answer 1

ответ: 216 см- периметр, 2660 см²- площадь

объяснение:

1)70-32=38(см)- ширина прямоугольника

2)P= (70+38)×2=216(cм)

3)S=70×38=2660(см²)

ответ: 216 см- периметр прямоугольника

2660 см²- площадь прямоугольника

Answer 2

7дм=70см

a=70см

b=(70-32)=38см

P=(70+38)*2=216

S=70*38=2660см²=0,2660м²

Answer 3

Problem Analysis

We are given that the length of a rectangle is 7 dm, which is 32 cm longer than the width. We need to find the perimeter and area of this rectangle.

Solution

Let's denote the width of the rectangle as x cm. According to the given information, the length of the rectangle is 7 dm, which is equal to 70 cm. We can set up the following equation to represent the relationship between the length and width:

70 cm = x cm + 32 cm

To find the value of x, we can subtract 32 cm from both sides of the equation:

70 cm - 32 cm = x cm

Simplifying the equation, we get:

38 cm = x cm

So, the width of the rectangle is 38 cm.

Perimeter of the Rectangle

The perimeter of a rectangle is given by the formula:

Perimeter = 2 * (Length + Width)

Substituting the values, we have:

Perimeter = 2 * (70 cm + 38 cm)

Calculating the perimeter, we get:

Perimeter = 2 * 108 cm = 216 cm

Therefore, the perimeter of the rectangle is 216 cm.

Area of the Rectangle

The area of a rectangle is given by the formula:

Area = Length * Width

Substituting the values, we have:

Area = 70 cm * 38 cm

Calculating the area, we get:

Area = 2660 cm^2

Therefore, the area of the rectangle is 2660 cm^2.