Question

в компьютерный класс купили столы. в первый раз купили 8 столов, но во второй раз- 5. таким образом вторая покупка была в 132 евро дешевле. сколько стоил 1 стоил, и сколько стоило всего столов?

Answer 1

Ответ:

44 евро, 528 евро

Пошаговое объяснение:

1) 8-5 = 3 (ст.) - разница

2) 3 стола = 132 евро

3) 132: 3 = 44 (евр.) - стоит один стол

4) 8+5=12 (ст.) - купили всего

5) 12*44= 528 (Ев.) - стоили 12 столов

Answer 2

Problem Analysis

We are given that a computer class bought tables. In the first purchase, they bought 8 tables, and in the second purchase, they bought 5 tables. The second purchase was 132 euros cheaper than the first purchase. We need to find the cost of one table and the total cost of all the tables.

Solution

Let's assume the cost of one table is x euros.

The cost of the first purchase, with 8 tables, would be 8x euros.

The cost of the second purchase, with 5 tables, would be 5x euros.

According to the problem, the second purchase was 132 euros cheaper than the first purchase. So we can set up the following equation:

8x - 5x = 132

Simplifying the equation, we get:

3x = 132

Dividing both sides of the equation by 3, we find:

x = 44

Therefore, the cost of one table is 44 euros.

To find the total cost of all the tables, we can multiply the cost of one table by the total number of tables purchased:

Total cost = 44 euros/table * (8 tables + 5 tables)

Simplifying the equation, we get:

Total cost = 44 euros/table * 13 tables

Total cost = 572 euros

Therefore, the total cost of all the tables is 572 euros.

Answer

The cost of one table is 44 euros, and the total cost of all the tables is 572 euros.