Question

Два друга договорились о встрече и вышли одновременно из сво- их домов навстречу друг другу. Один мальчик шел со скоростью 50 м/мин и прошел до встречи 420 метров. Второй мальчик шел со скоростью 70 м/мин. Какое расстояние до встречи прошел второй мальчик? ​

Answer 1

И так, для начала узнаём, за сколько времени прошёл первый мальчик:
1) 420:50= 8,4 часа
затем уже узнаём сколько прошёл второй мальчик:
2) 70*8,4= 588 м прошёл второй мальчик

Answer 2

Ответ:

Р: 1) 70-50=20(м/мин) Vсбл.

2) 420:20= 21(мин)врем

3)70*21= 270(м)расс.

О:270 метровдо встречи прошёл второй мальчик.

Пошаговое объяснение:

Удачоюи друг мой , я отличник по математике

Answer 3

Problem Analysis

Two friends are walking towards each other from their respective houses. The first boy walks at a speed of 50 m/min and covers a distance of 420 meters until they meet. The second boy walks at a speed of 70 m/min. We need to find the distance the second boy traveled before they met.

Solution

To find the distance the second boy traveled, we can use the concept of relative speed. The relative speed is the sum of the speeds of the two boys since they are moving towards each other.

Let's assume the distance the second boy traveled is x meters.

The time taken by the first boy to cover 420 meters is given by: Time taken by the first boy = Distance / Speed = 420 / 50 = 8.4 minutes

The time taken by the second boy to cover x meters is given by: Time taken by the second boy = Distance / Speed = x / 70

Since they both started at the same time and met after 8.4 minutes, we can equate the two time expressions:

8.4 = x / 70

To find x, we can multiply both sides of the equation by 70:

8.4 * 70 = x

Now, let's calculate the value of x:

x = 8.4 * 70 = 588 meters

Therefore, the second boy traveled a distance of 588 meters before they met.

Answer

The second boy traveled a distance of 588 meters before they met.