Question

2) [2(y - 2) > 3y +1 5 (y+1) < 4y + 3;пж 6класс 970номер​

Answer 1

Пошаговое объяснение:

ответ: y€ (-бесконечность;-5]

Answer 2

To solve the inequalities, let's work on them one by one:

1. 2(y - 2) > 3y + 1

First, distribute 2 to both terms inside the parentheses: 2y - 4 > 3y + 1

Next, let's isolate the y term on one side. Subtract 2y from both sides: -4 > y + 1

Now, let's isolate the y term on the other side. Subtract 1 from both sides: -4 - 1 > y

Simplifying further: -5 > y

So the solution to the first inequality is y < -5.

2. 5(y + 1) < 4y + 3

First, distribute 5 to both terms inside the parentheses: 5y + 5 < 4y + 3

Next, let's isolate the y term on one side. Subtract 4y from both sides: 5y - 4y + 5 < 3

Simplifying further: y + 5 < 3

Now, let's isolate the y term on the other side. Subtract 5 from both sides: y + 5 - 5 < 3 - 5

Simplifying further: y < -2

So the solution to the second inequality is y < -2.

Therefore, the solutions to the given system of inequalities are y < -5 and y < -2.