Question

Пж допоможіть номер64У трьох ящиках були цукерки.Коли з першого ящика переклали до третього -3,2кг,а з другого до третього -4,25кг,то в усіх ящиках стало по 15,1кг цукерок.Скільки кг цукерок було в кожному ящику спочатку?​

Answer 1

Ответ:

1)15.1-3.2=12.99(кг)

2)12.99-4.25=8.74(кг)-було в третій скриньці (было в третьем ящике)

3)15.1+3.2=18.3(кг)- було в першій скриньці (было в первом ящике)

4)15.1+4.25=19.26(кг)

відповідь: у першому ящику було 18.3 кг у другому 19.26 кг у третьому 12.99 кг

ответ: в первом ящике было 18.3 кг во вотором 19.26 кг в третьем 12.99 кг

Пошаговое объяснение:

недавно проходили

Answer 2

Problem Analysis

We are given three boxes of candies. When we transfer candies from the first box to the third box, the weight decreases by 3.2 kg. Similarly, when we transfer candies from the second box to the third box, the weight decreases by 4.25 kg. After the transfers, the total weight of candies in all three boxes is 15.1 kg. We need to determine the initial weight of candies in each box.

Solution

Let's assume the initial weights of candies in the first, second, and third boxes are x, y, and z kg, respectively.

According to the given information, we can set up the following equations:

Equation 1: x - 3.2 = z Equation 2: y - 4.25 = z Equation 3: x + y + z = 15.1

We can solve this system of equations to find the values of x, y, and z.

Solving the Equations

Let's solve the system of equations using substitution or elimination method.

From Equation 1, we can express x in terms of z: x = z + 3.2

Substituting this value of x in Equation 3, we get: (z + 3.2) + y + z = 15.1 2z + y = 11.9 ---(Equation 4)

From Equation 2, we can express y in terms of z: y = z + 4.25

Substituting this value of y in Equation 4, we get: 2z + (z + 4.25) = 11.9 3z + 4.25 = 11.9 3z = 11.9 - 4.25 3z = 7.65 z = 7.65 / 3 z = 2.55

Now, we can substitute the value of z back into Equation 1 to find x: x = 2.55 + 3.2 x = 5.75

Similarly, we can substitute the value of z back into Equation 2 to find y: y = 2.55 + 4.25 y = 6.8

Answer

Therefore, the initial weights of candies in each box were: - First box: 5.75 kg - Second box: 6.8 kg - Third box: 2.55 kg

Please let me know if you need any further assistance!