Question

-1\ \frac{\ 1}{6}+\left(-2\ \frac{\ 3}{8}\right)

Answer 1

Ответ:
Что
Что
Пошаговое объяснение:

Answer 2

To subtract these mixed numbers, we need to convert them to improper fractions and then perform the subtraction. Let's start with the first mixed number:

-1\ \frac{1}{6}

To convert this to an improper fraction, we multiply the whole number (-1) by the denominator of the fraction (6) and then add the numerator (1). This gives us:

-1\ \frac{1}{6} = -\frac{6}{6} + \frac{1}{6} = -\frac{6 + 1}{6} = -\frac{7}{6}

Now let's convert the second mixed number:

-2\ \frac{3}{8}

Using the same process:

-2\ \frac{3}{8} = -\frac{2}{1}\ \frac{3}{8} = -\frac{16}{8} + \frac{3}{8} = -\frac{16 + 3}{8} = -\frac{19}{8}

Now we can subtract the two fractions:

-\frac{7}{6} - \frac{19}{8}

To subtract fractions, we need a common denominator. The least common multiple of 6 and 8 is 24, so let's convert the fractions to have a denominator of 24:

-\frac{7}{6} = -\frac{7}{6} \times \frac{4}{4} = -\frac{28}{24} -\frac{19}{8} = -\frac{19}{8} \times \frac{3}{3} = -\frac{57}{24}

Now we can subtract:

-\frac{28}{24} - \frac{57}{24} = -\frac{28 - 57}{24} = -\frac{85}{24}

Therefore, -1\ \frac{1}{6} + \left(-2\ \frac{3}{8}\right) equals -\frac{85}{24}.