Question

Вероятность попадания в мишень при одном выстреле 0,7. Стрелок делает два выстрела по мишени. Вероятность того, что он попадет в мишень только один раз, равна …

Answer 1

Ответ:

0,21

Пошаговое объяснение:

Шанс промаха 1-0,7=0,3

При двух выстрелах вероятности перемножаются

Ответ: 0,7*0,3=0,21

Answer 2

Probability of Hitting the Target

The probability of hitting the target with one shot is 0.7. Now, the shooter takes two shots at the target. We want to find the probability that the shooter hits the target only once.

Calculating the Probability

To calculate the probability that the shooter hits the target only once, we can use the complement rule. This rule states that the probability of an event occurring is 1 minus the probability of the event not occurring.

The probability of hitting the target only once can be calculated using the formula: P(hitting the target only once) = P(hitting the target with the first shot) * P(missing the target with the second shot) + P(missing the target with the first shot) * P(hitting the target with the second shot)

Using the given probability of hitting the target (0.7), we can calculate the probability of hitting the target only once.

Calculation

P(hitting the target only once) = (0.7 * 0.3) + (0.3 * 0.7) = 0.21 + 0.21 = 0.42

So, the probability that the shooter hits the target only once is 0.42.