Question

89:48+96=? 85:5+120×4=? 100-47×2=? 84:4×8=? 8т-3т178кг 19т160км+840кг​

Answer 1

Вот , пожалуйста !)))))))

Answer 2

Ответ:

1)89:48+96= 2 (ост. 3) +96= 98 (ост. 3)

2)85:5+120*4= 17+480= 497

3)100-47*2=100-94=6

4)84:4*8= 21*8= 168

5) 8т - 3 т 178 кг= 4т 822кг

6) 19т 160км + 840кг= 20т

Answer 3

To solve the given mathematical equations, let's go through each one step by step:

1. 89:48 + 96: To add these two numbers, we simply add the digits in the corresponding places. Carrying over is required when the sum of two digits is greater than 9. - The sum of the units place (9 + 6) is 15. Write down 5 and carry over 1. - The sum of the tens place (8 + 9 + 1) is 18. Write down 8 and carry over 1. - The sum of the hundreds place (4 + 6 + 1) is 11. Write down 1 and carry over 1. - The sum of the thousands place (0 + 0 + 1) is 1. Write down 1. - Therefore, 89:48 + 96 = 1,185.

2. 85:5 + 120×4: First, let's perform the multiplication operation, and then we'll add the two results. - 120 × 4 = 480. - Now, let's perform the division operation. - 85:5 = 17. - Finally, let's add the two results: 17 + 480 = 497.

3. 100 - 47 × 2: To solve this equation, we need to perform the multiplication first and then subtract the result from 100. - 47 × 2 = 94. - Now, let's subtract 94 from 100: 100 - 94 = 6.

4. 84:4 × 8: First, let's perform the division operation, and then we'll multiply the result by 8. - 84:4 = 21. - Now, let's perform the multiplication operation: 21 × 8 = 168.

5. 8т - 3т178кг + 19т160км + 840кг: It seems like you have provided a combination of numbers and units. To solve this equation, we need to perform addition and subtraction operations separately for the numbers and the units. - For the numbers: 8т - 3т178кг + 19т160км + 840кг = 8т + 19т - 3т178кг + 840кг = 24т - 3т178кг + 840кг. - For the units: т - т178кг + т160км + кг = т + т - т178кг + кг = 2т - т178кг + кг. - Therefore, the simplified equation is 24т - 3т178кг + 840кг = 2т - т178кг + кг.

Please note that the given equation contains a combination of numbers and units, which makes it difficult to provide a specific numerical answer without knowing the values of the units.