Question

Имеется 10 последовательных натуральных чисел. Могло ли оказаться так, что первое число делится на 1, второе на 2, третье на 3,.... Девятое на 9 а десятое на 20?

Answer 1

Ответ:

да

Пошаговое объяснение:

а б в оооооооооооооооооооооооооооооооооооочень

Answer 2

Ответ:

Пошаговое объяснение:

сәлем беру керек болып тұр деп кім

Answer 3

Checking the Possibility of Consecutive Natural Numbers Meeting Specific Divisibility Criteria

To determine whether it is possible for 10 consecutive natural numbers to meet the given divisibility criteria, let's analyze the requirements.

Given Criteria: - The first number should be divisible by 1. - The second number should be divisible by 2. - The third number should be divisible by 3. - The ninth number should be divisible by 9. - The tenth number should be divisible by 20.

Analysis:

1. The first number being divisible by 1 is trivial, as all numbers are divisible by 1. 2. The second number being divisible by 2 is also straightforward, as every even number is divisible by 2. 3. The third number being divisible by 3 is feasible, as there are consecutive numbers that are divisible by 3 (e.g., 3, 6, 9, 12, etc.). 4. The ninth number being divisible by 9 is possible, as there are consecutive numbers that are divisible by 9 (e.g., 9, 18, 27, 36, etc.). 5. The tenth number being divisible by 20 is not possible with the given criteria, as there are no 10 consecutive natural numbers where the last number is divisible by 20.

Conclusion:

Based on the analysis, it is not possible for 10 consecutive natural numbers to meet the given divisibility criteria, specifically the requirement for the tenth number to be divisible by 20.

[[6 #]], [[7 #]]