Question

296. Измерения прямоугольного параллелепипеда равны 6 дм, 12 дм и 17 дм. Найдите площадь поверхности параллелепипеда.​

Answer 1

Ответ:

S=a*b*h

S= 6*12*7

S=504

Пошаговое объяснение:

вроде так

Answer 2

Calculation of Surface Area of a Rectangular Parallelepiped

To find the surface area of a rectangular parallelepiped, we need to calculate the areas of all six faces and then sum them up.

Given the dimensions of the rectangular parallelepiped as 6 dm, 12 dm, and 17 dm, we can label the sides as follows: - Length (l) = 17 dm - Width (w) = 12 dm - Height (h) = 6 dm

The surface area of a rectangular parallelepiped can be calculated using the formula:

Surface Area = 2lw + 2lh + 2wh

Substituting the given values into the formula, we get:

Surface Area = 2(17 dm * 12 dm) + 2(17 dm * 6 dm) + 2(12 dm * 6 dm)

Simplifying the equation, we have:

Surface Area = 2(204 dm²) + 2(102 dm²) + 2(72 dm²)

Surface Area = 408 dm² + 204 dm² + 144 dm²

Surface Area = 756 dm²

Therefore, the surface area of the rectangular parallelepiped is 756 square decimeters.