Question

Известно что 2 5 класа пошли в кино 3 7 на выставку сколько учащихся в класе если ихменьше 40

Answer 1

Ответ:

35 человек

Пошаговое объяснение:

2/5 - должно быть целым числом

3/7 - должно быть целым числом

Значит исходное количество детей должно быть кратно 5 и 7.

НОК (5, 7)=35.

Еще 35<40. Значит это искомое число.

Answer 2

Ответ:

35 учащихся в классе

Пошаговое объяснение:

По условию, 2/5 класса пошли в кино, а 3/7 на выставку.

2/5 + 3/7 = 14/35 + 15/35 = 29/35 учащихся пошли в кино и на выставку

Все учащиеся составляют 1 (одна целая часть), тогда:

1 - 29/35 = 35/35 - 29/35 = 6/35 учащихся никуда не пошли

Отсюда следует, что общее количество учащихся равно общему знаменателю двух дробей 2/5 и 3/7, т.е. количество учащихся = 35.

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35*2/5 = 14 пошли в кино

35*3/7 = 15 на выставку.

35*6/36 = 6 человек никуда не пошли

Answer 3

Calculating the Number of Students in Each Class

To calculate the number of students in each class, we can use a system of linear equations based on the information provided. Let's denote the number of students in the 2nd class as x and the number of students in the 5th class as y. According to the given information, 2 classes went to the cinema, and 3 classes went to the exhibition. This can be represented by the following equations:

1. x + y = 2 (Two classes went to the cinema) 2. x + y = 3 (Three classes went to the exhibition)

However, we also know that the total number of students in both classes is less than 40. This gives us the inequality:

3. x + y < 40

Let's solve this system of equations and the inequality to find the possible values for x and y.

Solving the System of Equations and Inequality

By subtracting equation 1 from equation 2, we get 0 = 1, which is not possible. This means there is no solution that satisfies both equations. However, we can still solve the inequality x + y < 40 to find the possible combinations of x and y that satisfy this condition.

Possible Combinations of Students in Each Class

Based on the given information, the possible combinations of students in the 2nd and 5th classes that satisfy the condition x + y < 40 are:

- x = 1, y = 1 (Total students = 2) - x = 2, y = 1 (Total students = 3) - x = 1, y = 2 (Total students = 3)

These combinations satisfy the condition that the total number of students in both classes is less than 40.

I hope this helps! If you have any further questions, feel free to ask.