Question

Представить в виде многочлена 1) (у-6)²=2) (2а-3б)²=3) (3х+х³)²=4) (m-6) (m+6)=5) ( 7x+10y) (10y-7x)= ​

Answer 1

$1) \: (y - 6) {}^{2} = y {}^{2} - 12y + 36 \\ 2) \: (2a - 3b) {}^{2} = 4a {}^{2} - 12ab + 9b {}^{2} \\ 3) \: (3x + x {}^{3} ) {}^{2} = 9x {}^{2} + 6x {}^{4} + x {}^{6} \\ 4) \: (m - 6)(m + 6) = m {}^{2} - 36 \\ 5) \: (7x + 10y)(10y - 7x) = 100y {}^{2} - 49x {}^{2}$

Answer 2

1) (у-6)² = у² - 12у + 36 2) (2а-3б)² = 4a² - 12ab + 9b² 3) (3х+х³)² = 9x² + 6x⁴ + x⁶ 4) (m-6) + (m+6) = 2m 5) (+7x+10y) + (10y-7x) = 20y