Question

в десяти одинаковых вазочках поровну были разложаны леденцы. Из каждой вазочки забрали по 20 леденцов, после чего осталось во всех вазочках вмесье столько леденцов, сколько было до этого в двух вазочках. сколько леденцовбыло в одной вазочке вначале.

Answer 1

Ответ:

25 леденцов

Пошаговое объяснение:

Пусть х - количество леденцов в вазочке, когда по 20 штук достали, тогда х+20 - исходное количество леденцов, тогда:

10*х=2*(х+20)

10х=2х+40

10х-2х=40

8х=40

х=5(леденцов в вазочке после того, как достали 20)

5+20=25(леденцов) было в вазочках изначально

Answer 2

Ответ:25


Я подбирал. 25 - 20=5
5*10=50
25+25=50

Answer 3

Solution:

Let's solve this step by step.

1. Initial Distribution of Candies: - Initially, there were an equal number of candies in each of the ten vases. - Let's denote the initial number of candies in each vase as x.

2. Candies Taken Out: - From each vase, 20 candies were taken out. - So, after taking out 20 candies from each vase, there were initially x - 20 candies left in each vase.

3. Remaining Candies: - After taking out 20 candies from each vase, the total number of remaining candies in all the vases was equal to the initial number of candies in two vases. - The initial number of candies in two vases is 2x.

4. Equation: - We can form the following equation based on the given information: - 10 * (x - 20) = 2x

5. Solving for x: - Let's solve the equation to find the initial number of candies in each vase, denoted by x.

   10 * (x - 20) = 2x
   10x - 200 = 2x
   10x - 2x = 200
   8x = 200
   x = 25
   

6. Conclusion: - Therefore, there were 25 candies in each vase initially.

So, the initial number of candies in each vase was 25.