
Найдите площадь и периметр 2/3 прямоугольника Периметр которого 34 см а длина 11 см


Ответы на вопрос

Ответ: ширина прямоугольника 6см
площадь равна 66см²
Пошаговое объяснение:
11*2=22 6*11=66
34-22=12
12/6=2
(6+6)+(11+11)=12+22=34



I can understand and communicate in Russian. I can help you with various tasks, such as generating creative content, finding information, or solving problems.
To answer your question, I will use the web search results from my internal tool.
The area and perimeter of a rectangle are calculated by the formulas: $$S = a \cdot b$$ and $$P = 2(a + b)$$, where $$a$$ and $$b$$ are the length and width of the rectangle.
To find the area and perimeter of $$2/3$$ of a rectangle, we need to multiply the original area and perimeter by $$2/3$$.
The original area of the rectangle is $$S = 11 \cdot b$$, where $$b$$ is the unknown width.
The original perimeter of the rectangle is $$P = 34$$, according to the problem statement.
We can use the perimeter formula to find the width: $$34 = 2(11 + b)$$, which implies $$b = 6$$.
Therefore, the original area of the rectangle is $$S = 11 \cdot 6 = 66$$ cm$$^2$$.
The area of $$2/3$$ of the rectangle is $$2/3 \cdot S = 2/3 \cdot 66 = 44$$ cm$$^2$$.
The perimeter of $$2/3$$ of the rectangle is $$2/3 \cdot P = 2/3 \cdot 34 = 22.67$$ cm.
I hope this helps. For more information, you can check these web pages: [How to calculate the area and perimeter of a rectangle](https://ru.wikihow.com/%D0%B2%D1%8B%D1%87%D0%B8%D1%81%D0%BB%D0%B8%D1%82%D1%8C-%D0%BF%D0%BB%D0%BE%D1%89%D0%B0%D0%B4%D1%8C-%D0%B8-%D0%BF%D0%B5%D1%80%D0%B8%D0%BC%D0%B5%D1%82%D1%80-%D0%BF%D1%80%D1%8F%D0%BC%D0%BE%D1%83%D0%B3%D0%BE%D0%BB%D1%8C%D0%BD%D0%B8%D0%BA%D0%B0), [How to find the sides of a rectangle with a known perimeter and area](https://easy-math.ru/how-to-find-the-sides-of-a-rectangle-with-a-known-perimeter-and-area/), [Perimeter. How to find the perimeter of a rectangle, square and triangle](https://math-prosto.ru/ru/pages/perimeter/perimeter/).


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