Question

На шахматном турнире ученики 6-го класса получили 12, 12, 12, 13, 10, 9, 12, 10 очков. Найдите среднее арифметическое и моду. ​ [3] ПРОШУ ПОМОГИТЕЕЕ

Answer 1

Ответ:

Мо(мода)

х (среднее арифметическое)

Ряд:9;10;10;12;12;12;12;13.

Мо-12

х=9+10*2+12*4+13÷8=11,25

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Answer 2

Calculating the Average and Mode of Scores in a Chess Tournament

To find the average and mode of the scores obtained by the 6th-grade students in a chess tournament, we can use the following steps:

1. Calculating the Average (Mean): - To find the average, we sum up all the scores and then divide by the total number of scores.

2. Calculating the Mode: - The mode is the value that appears most frequently in a set of data.

Let's calculate both the average and the mode based on the scores provided.

Calculating the Average (Mean)

The average (mean) score can be calculated by summing up all the scores and then dividing by the total number of scores.

The given scores are: 12, 12, 12, 13, 10, 9, 12, 10.

To find the average: (12 + 12 + 12 + 13 + 10 + 9 + 12 + 10) / 8 = 90 / 8 = 11.25

So, the average (mean) score is 11.25.

Calculating the Mode

The mode is the value that appears most frequently in a set of data.

In this case, the mode of the given scores is 12, as it appears three times, which is more than any other score.

Therefore, the mode of the scores is 12.

In summary, the average (mean) score is 11.25 and the mode of the scores is 12.