Question

B4-b2=16. b5-b3=32 найти b1​

Answer 1

Ответ:

b1=8/3

Пошаговое объяснение:

bn=b(n-1)q

bn=b1q^(n-1)

{b1q³-b1q=16 { b1q(q²-1)=16

{b1q⁴-b1q²=32 {b1q²(q²-1)=32

q=32/16=2

b1=16/(q(q²-1))=16/(2(4-1))=16/6=8/3

Answer 2

To find the value of b1, we can work backward from the given equations.

Given: B4 - B2 = 16 -- (Equation 1) B5 - B3 = 32 -- (Equation 2)

Let's express B2 and B3 in terms of B1 and use these equations to find the value of B1.

We know that the difference between the consecutive terms in a sequence is constant. Therefore, we can express B2 and B3 in terms of B1:

B2 = B1 - 1 -- (Equation 3) B3 = B1 - 2 -- (Equation 4)

Now, substitute the values of B2 and B3 in Equations 1 and 2:

(B1 - 1) - B1 = 16 -- (Equation 1) (B1 - 2) - B1 = 32 -- (Equation 2)

Simplifying the equations:

-B1 - (-1) = 16 -B1 + 1 = 16 -B1 = 16 - 1 -B1 = 15 B1 = -15

And

-B1 - (-2) = 32 -B1 + 2 = 32 -B1 = 32 - 2 -B1 = 30 B1 = -30

There seems to be a contradiction in the results. Please double-check the given information or equations to ensure their accuracy.