Question

1) a³a²+ 6a -21 when a = - 4

Answer 1

Пошаговое объяснение:

а³а²+6а-21=(-4)³×(-4)²+6×(-4)-21=

= -64×16-24-21= -1024-24-21=

= -(1024+24+21)= -1069

Answer 2

Ответ:

-1069

Пошаговое объяснение:

а³а² + 6а - 21 = а⁵ + 6а - 21

а = -4

а⁵ + 6а - 21 = (-4)⁵ + 6*(-4) - 21 =

-1024 + (-24) - 21 = -1024 - 24 - 21 = -1069

Answer 3

To evaluate the expression a³a² + 6a - 21 when a = -4, we substitute -4 for the variable a:

(-4)³(-4)² + 6(-4) - 21

Let's calculate each part separately:

(-4)³ = -4 * -4 * -4 = -64

(-4)² = -4 * -4 = 16

Now we substitute the calculated values back into the expression:

-64 * 16 + 6(-4) - 21

Next, we simplify the expression:

-1024 + (-24) - 21

Combining like terms:

-1024 - 24 - 21

Finally, we perform the arithmetic:

-1069 - 21

-1090

Therefore, when a = -4, the expression a³a² + 6a - 21 evaluates to -1090.