Question

B-12=32 a+19=41 46+x=54 x-200=800 a-37=63 b+28=56

Answer 1

Ответ:

(b)44-12=32
(a)22+19=41

46+(x)8=54

(x)1000-200=800

(a)100-37=63

(b)28+28=56

Answer 2

To solve the given equations, let's solve them one by one:

1. B - 12 = 32 Adding 12 to both sides, we get: B = 32 + 12 B = 44

2. a + 19 = 41 Subtracting 19 from both sides, we get: a = 41 - 19 a = 22

3. 46 + x = 54 Subtracting 46 from both sides, we get: x = 54 - 46 x = 8

4. x - 200 = 800 Adding 200 to both sides, we get: x = 800 + 200 x = 1000

5. a - 37 = 63 Adding 37 to both sides, we get: a = 63 + 37 a = 100

6. b + 28 = 56 Subtracting 28 from both sides, we get: b = 56 - 28 b = 28

So the solutions to the equations are: B = 44 a = 22 x = 8 x = 1000 a = 100 b = 28