Question

1) 4/13+7/13-2/132) 1-12/19​

Answer 1

1. 4/13 + 7/13 - 2/13 = (4 + 7 - 2) / 13 = 9/13

Ответ: 9/13

2. 1 - 12/19 = (19/19) - (12/19) = (19 - 12) / 19 = 7/19

Ответ: 7/19

Answer 2

To solve the given expressions, let's simplify them step by step:

1. $\frac{4}{13} + \frac{7}{13} - \frac{2}{132}$

First, we notice that the fractions have a common denominator of 13. We can add the numerators and keep the denominator the same:

$\frac{4 + 7}{13} - \frac{2}{132}$

Simplifying the numerator:

$\frac{11}{13} - \frac{2}{132}$

Now, we need to find a common denominator between 13 and 132. Since 132 is a multiple of 13, we can use 132 as the common denominator:

$\frac{11}{13} - \frac{2}{132} = \frac{11}{13} - \frac{2}{132} \times \frac{1}{1}$

$\frac{11}{13} - \frac{2}{132} = \frac{11}{13} - \frac{2}{13 \times 11}$

Now that the denominators are the same, we can subtract the fractions:

$\frac{11}{13} - \frac{2}{13 \times 11} = \frac{11}{13} - \frac{2}{143}$

To subtract the fractions, we need a common denominator of 143:

$\frac{11}{13} - \frac{2}{143} = \frac{11}{13} \times \frac{11}{11} - \frac{2}{143}$

$\frac{11 \times 11}{13 \times 11} - \frac{2}{143} = \frac{121}{143} - \frac{2}{143}$

Now that the denominators are the same, we can subtract the fractions:

$\frac{121}{143} - \frac{2}{143} = \frac{121 - 2}{143}$

Simplifying the numerator:

$\frac{119}{143}$

Therefore, the simplified expression is $\frac{119}{143}$.

2. $1 - \frac{12}{19}$

The whole number 1 can be represented as a fraction with a denominator of 1:

$\frac{1}{1} - \frac{12}{19}$

Now, we need a common denominator between 1 and 19. We can use 19 as the common denominator:

$\frac{1}{1} - \frac{12}{19} = \frac{1}{1} \times \frac{19}{19} - \frac{12}{19}$

$\frac{19}{19} - \frac{12}{19} = \frac{19 - 12}{19}$

Simplifying the numerator:

$\frac{7}{19}$

Therefore, the simplified expression is $\frac{7}{19}$.