Question

1).2х-4х-х=15 2).-3(2+х)=2-х 3).0,6(х-5)-0,2(5-2х)=х+8. срочнооооооо пжжжжж

Answer 1

1)

2x-4x-x=15

-3x=15

x=-5

2)

3(2+x)=2-x

6+3x=2-x

2x=-4

x=-2

3)

0,6(x-5)-0,2(5-2x)=x+8

0,6x-3-1+0,4x=x+8

x-4=x+8

-4=8

Корней нет

Answer 2

1. To solve the first equation, we need to combine like terms on the left-hand side: 2x - 4x - x = -3x So, the equation becomes: -3x = 15 To isolate x, we need to divide both sides by -3: x = -5

Therefore, the solution to the first equation is x = -5.

2. For the second equation, we need to distribute the -3 on the left-hand side: -6 - 3x = 2 - x Next, we can add x to both sides to get all the x terms on one side: -6 - 2x = 2 Then, we can subtract 6 from both sides to isolate the constant term: -2x = 8 Finally, we can divide both sides by -2 to solve for x: x = -4

Therefore, the solution to the second equation is x = -4.

3. To solve the third equation, we first need to distribute the coefficients: 0.6x - 3 - 0.2(5) + 0.4x = x + 8 Simplifying, we get: 0.6x - 1 - 0.4x = x + 8 Next, we can combine like terms on each side: 0.2x - 1 = x + 8 Subtracting 0.2x from both sides: -1 = 0.8x + 8 Subtracting 8 from both sides: -9 = 0.8x Finally, we can solve for x by dividing both sides by 0.8: x = -11.25

Therefore, the solution to the third equation is x = -11.25.