Question

Y=2lnx y'= решитепожалуйста

Answer 1

У’=1/х
Производная константы 0

Answer 2

To find the derivative of y = 2ln(x), we will use the chain rule.

Recall that the chain rule states:

(d/dx) f(g(x)) = f'(g(x)) * g'(x)

Let's apply this to our problem. We can rewrite y as:

y = 2 * ln(x)

Let g(x) = ln(x). Then f(g) = 2g.

Using the chain rule, we have:

y' = (d/dx) (2 * ln(x)) = 2 * (d/dx) ln(x) (using the product rule) = 2 * (1/x) (using the derivative of ln(x)) = 2/x

Therefore, the derivative of y = 2ln(x) is y' = 2/x.