Question

(-3b-1)•(-2)+(1-3b)•4 если b=1; b=0; b=-1

Answer 1

Проще всего прийти к успеху, раскрывая скобки и подставляя в получившееся выражение нужные значения b.

Ответ: 0; 6; 12.

Answer 2

To solve this expression, we can simply substitute the given values of b and simplify the expression using the order of operations (PEMDAS).

For b=1:

(-3b-1)•(-2)+(1-3b)•4 = (-3(1)-1)•(-2)+(1-3(1))•4 = (-4)•(-2)+(1-3)•4 = 8 + (-2) = 6

For b=0:

(-3b-1)•(-2)+(1-3b)•4 = (-3(0)-1)•(-2)+(1-3(0))•4 = (-1)•(-2)+(1-0)•4 = 2 + 4 = 6

For b=-1:

(-3b-1)•(-2)+(1-3b)•4 = (-3(-1)-1)•(-2)+(1-3(-1))•4 = (2)•(-2)+(4) = -4 + 4 = 0

Therefore, the values of the expression for b=1, b=0, and b=-1 are 6, 6, and 0, respectively.