Question

(b-4)·(b+4)-(b-3)·(b+5)=

Answer 1

B^2-16-(b^2-3b+5b-15)=b^2-16-b^2+3b-5b-15=-2b-31
Вроде так.

Answer 2

(b-4)•(b+4)-(b-3)•(b+5)=b^2+4b-4b-16-(b^2+5b-3b-15)=b^2-16-b^2-5b+3b+15=-16-5b+3b=-16-2b

Answer 3

Let's simplify the expression using the distributive property:

(b-4)·(b+4)-(b-3)·(b+5)

= b(b+4) - 4(b+4) - (b-3)(b+5)

= b^2 + 4b - 4b - 16 - (b^2 + 5b - 3b - 15)

= b^2 + 4b - 4b - 16 - b^2 - 2b - 15

= -2b - 31

Therefore, (b-4)·(b+4)-(b-3)·(b+5) simplifies to -2b - 31.