Question

1)(8y+1)⋅(7y−2)=(56y−3)(y+1) 2)х^2+11x+24=0 3)56am+14mu−16au−49m^2 ПОМОГИТЕ

Answer 1

Ответ:

Пошаговое объяснение:

1)(8y+1)⋅(7y−2)=(56y−3)(y+1);

56y^2+7y-16y-2-56y^2+3y-56y+3=0;

-62y+1=0;

62y=1;

y=1/62;

Answer 2

1. To solve the equation:

(8y+1)⋅(7y−2)=(56y−3)(y+1)

First, expand the left-hand side:

56y^2 - 15y - 2 = 56y^2 + 53y - 3

Simplifying and rearranging terms, we get:

68y = 1

Therefore, the solution is:

y = 1/68

2. To solve the equation:

x^2 + 11x + 24 = 0

We can factor the left-hand side as:

(x + 3)(x + 8) = 0

Therefore, the solutions are:

x = -3 or x = -8

3. To simplify the expression:

56am + 14mu − 16au − 49m^2

We can factor out a common factor of 7m:

7m(8a + 2u - 2a - 7m)

Simplifying, we get:

7m(6a + 2u - 7m)

Therefore, the simplified expression is:

7m(6a + 2u - 7m)