Question

(13/42+41/12)-14/7=+(12/6+44/84)-10/12

Answer 1

(13/42+41/12)-14/7+(12/6+44/84)-10/12=145/84+142/84=287/84=41/12=
=3 5/12
1)13/42(*2)+41/12(*7)=26/84+287/84=313/84
2)313/84-14/7(*12)=313/84-168/84=145/84
3)12/6(*14)+44/84=168/84+44/84=212/84
4)212/84-10/12(*7)=212/84-70/84=142/84

Answer 2

Let's simplify the left-hand side of the equation first:

(13/42 + 41/12) - 14/7

To add fractions, we need to find a common denominator. In this case, the smallest common multiple of 42, 12, and 7 is 252.

(13/42) * (6/6) = 78/252 (41/12) * (21/21) = 861/252 (14/7) * (36/36) = 504/252

So the equation becomes:

78/252 + 861/252 - 504/252

Now we can combine the numerators:

(78 + 861 - 504)/252 = 435/252

Let's simplify the right-hand side of the equation next:

(12/6 + 44/84) - 10/12

Again, we need to find a common denominator. The smallest common multiple of 6, 84, and 12 is 252.

(12/6) * (42/42) = 252/252 (44/84) * (3/3) = 132/252 (10/12) * (21/21) = 210/252

So the equation becomes:

252/252 + 132/252 - 210/252

Now we can combine the numerators:

(252 + 132 - 210)/252 = 174/252

So the final equation is:

435/252 = 174/252

To solve for the unknown variable, we can cross-multiply:

435 * 252 = 174 * 252

110,340 = 43,848

Since this is a contradiction (110,340 cannot be equal to 43,848), the equation has no solution.