Question

45,9•(52+х)=0-75,3•(х-6)=0-25•(5,7+х)=0(12+х) •10=0​

Answer 1

Відповідь:

52+х=0           х-6=0       5,7+х=0     120+10х=0

х=-52               х=6           х=-5,7        10х=-120

                                                            х=-120/10

                                                            х=-12

Покрокове пояснення:

Answer 2

Let's solve each equation step by step:

1. 45.9 * (52 + x) = 0

First, distribute 45.9 to (52 + x):

45.9 * 52 + 45.9 * x = 0

Then, simplify:

2386.8 + 45.9x = 0

Next, move 2386.8 to the other side:

45.9x = -2386.8

Now, divide both sides by 45.9 to solve for x:

x = -2386.8 / 45.9

x ≈ -51.97

2. 0 - 75.3 * (x - 6) = 0

Distribute 75.3 to (x - 6):

0 - 75.3x + 451.8 = 0

Move 451.8 to the other side:

-75.3x = -451.8

Divide both sides by -75.3:

x = -451.8 / -75.3

x ≈ 6

3. 0 - 25 * (5.7 + x) = 0

Distribute 25 to (5.7 + x):

0 - 25 * 5.7 - 25 * x = 0

Simplify:

-142.5 - 25x = 0

Move -142.5 to the other side:

-25x = 142.5

Divide both sides by -25:

x = 142.5 / -25

x ≈ -5.7

4. (12 + x) * 10 = 0

Divide both sides by 10:

12 + x = 0

Move 12 to the other side:

x = -12

So, the solutions to the given equations are: x ≈ -51.97, 6, -5.7, -12.