Question

32+х=67. х+28=45. 84-х= 44. х-19=57

Answer 1

1. 32 + х = 67
    х = 67 - 32 
    х = 35
2. х + 28 = 45
    х = 45 - 28
    х = 17
3. 84 - х = 44
    х = 84 - 44
    х = 40
4. х - 19 = 57
    х = 57 + 19
    х = 76

Answer 2

32+х=67
х=67-32
х=35
32+35=67
67=67

х+28=45
х=45-28
х=27
27+28=45
45=45

х-19=57
х=19+57
х=76
76-19=57
57=57

Answer 3

To solve these equations for the variable "x", we can use basic algebraic operations such as addition, subtraction, multiplication, and division to isolate "x" on one side of the equal sign.

1. 32 + x = 67 Subtracting 32 from both sides, we get: x = 67 - 32 x = 35

Therefore, the solution to the first equation is x = 35.

2. x + 28 = 45 Subtracting 28 from both sides, we get: x = 45 - 28 x = 17

Therefore, the solution to the second equation is x = 17.

3. 84 - x = 44 Subtracting 84 from both sides, we get: -x = 44 - 84 -x = -40

Multiplying both sides by -1 (or dividing by -1 since multiplying by a reciprocal of -1) to isolate "x", we get: x = 40

Therefore, the solution to the third equation is x = 40.

4. x - 19 = 57 Adding 19 to both sides, we get: x = 57 + 19 x = 76

Therefore, the solution to the fourth equation is x = 76.

In summary, the solutions to the given equations are: x = 35, 17, 40, and 76.