Question

3 5/15+(d-1 7/16)=9 1/16 пж помогите решить

Answer 1

$3 \frac{5}{15} + (d - 1 \frac{7}{16} ) = 9 \frac{1}{16} \\ d - 1 \frac{7}{16} = 9 \frac{1}{16} - 3 \frac{5}{15} = \frac{145}{16} - \frac{50}{15} = \frac{2175 - 800}{240} = \frac{1375}{240} \\ d = \frac{1375}{240} + 1 \frac{7}{16} = \frac{1375}{240} + \frac{23}{16} = \frac{1375 + 345}{240} = \frac{1720}{240} = \frac{172}{24} = 7 \frac{4}{24} = 7 \frac{1}{6}$

Answer 2

To solve this equation, we need to isolate the variable "d" on one side of the equation.

First, let's simplify the left side of the equation by finding a common denominator:

3 5/15 + (d - 1 7/16) = 9 1/16

= 3 (5/15) + (d - 1) (16/16) - (7/16) = 9 (1/16)

= 3 (1/3) + (d - 1) - (7/16) = 9 (1/16)

= 10/3 + (d - 1) - (7/16) = 145/16

Next, let's combine like terms:

10/3 + d - 1 - 7/16 = 145/16

= 10/3 + d - 16/16 - 7/16 = 145/16

= 10/3 + d - 23/16 = 145/16

Now, let's isolate the variable "d" by adding 23/16 to both sides of the equation:

10/3 + d - 23/16 + 23/16 = 145/16 + 23/16

= 10/3 + d = 168/16

= 10/3 + d = 10 1/2

Finally, let's solve for "d" by subtracting 10/3 from both sides of the equation:

d = 10 1/2 - 10/3

= (31/2) - (10/3)

= (93/6) - (20/6)

= 73/6

Therefore, the solution to the equation 3 5/15 + (d - 1 7/16) = 9 1/16 is d = 73/6.