Question

1.24(х+2)=6(х-4) 2.В одной бочке в 3 раза больше бензина ,чем в другой. Если из первой бочке отлить 78 л бензина,а во вторую добавить 42 л,то бензина в бочке будет поровну. Сколько бензина в каждой бочке

Answer 1

Ответ:

Пошаговое объяснение:

1)

24(х+2)=6(х-4)

24х+48=6х-24

24х-6х=-48-24

18х=72

х=72:18

х=4

2)

В первой бочке было  3х литров

во второй х  л  

Из первой бочки отлили 78 л , значит

3х-78 л,  

Во вторую долили 42 л, получаем х+42  

Составим уравнение

3х-78=х+42

3х-х=78+42

2х=120

х=120:2

х=60 л было во второй бочке

60*3=180 л было в первой бочке

стало в первой бочке  180-78=102 л

стало во второй бочке  60+42=102 л

Answer 2

1. To solve the equation 1.24(x+2) = 6(x-4), we can start by simplifying both sides of the equation:

1.24(x+2) = 6(x-4) 1.24x + 2.48 = 6x - 24

Now, let's isolate the variable terms on one side and the constant terms on the other side:

1.24x - 6x = -24 - 2.48 -4.76x = -26.48

To solve for x, we divide both sides of the equation by -4.76:

x = (-26.48) / (-4.76) x ≈ 5.55

Therefore, the value of x is approximately 5.55.

2. Let's assume the amount of gasoline in the second barrel is represented by y liters. According to the given information, the amount of gasoline in the first barrel is three times greater, which would be 3y liters.

After removing 78 liters from the first barrel and adding 42 liters to the second barrel, the amounts of gasoline in the barrels become equal.

3y - 78 = y + 42

To solve for y, we can begin by subtracting y from both sides:

3y - y - 78 = 42

Simplifying the equation:

2y - 78 = 42

Next, we add 78 to both sides:

2y - 78 + 78 = 42 + 78

Simplifying further:

2y = 120

Finally, dividing both sides by 2:

y = 120 / 2 y = 60

So, there are 60 liters of gasoline in the second barrel, and in the first barrel, there are three times more, which is 3 * 60 = 180 liters.