Question

3√45+1,2√125+√20-√500

Answer 1

Каждое число под корнем разбил на множнители, а потом повыносил со знака корня:)

Answer 2

To simplify the expression, let's evaluate each square root individually:

√45 can be simplified as √(9 * 5). Since 9 is a perfect square, we can take it out of the square root, leaving us with 3√5.

√125 can be simplified as √(25 * 5). Again, we can take the perfect square 25 out of the square root, resulting in 5√5.

√20 can be simplified as √(4 * 5). Taking out the perfect square 4, we get 2√5.

√500 can be simplified as √(100 * 5). Taking out the perfect square 100, we get 10√5.

Now, let's substitute these simplified expressions back into the original expression:

3√45 + 1,2√125 + √20 - √500 = 3(3√5) + 1,2(5√5) + 2√5 - 10√5

Now, let's combine like terms:

= 9√5 + 6√5 + 2√5 - 10√5

Combining the coefficients:

= (9 + 6 + 2 - 10)√5 = 7√5

Therefore, the simplified expression is 7√5.