Question

(х-2)(х-3)(х-4)=(х-3)(х-4)(х-5)

Answer 1

(х-2)(х-3)(х-4)=(х-3)(х-4)(х-5)
сокращаем одинаковые множители в правой и левой частях уравнения
x-2=x-5
0=-3, не имеет решений

Answer 2

To solve the equation ${(x-2)(x-3)(x-4) = (x-3)(x-4)(x-5)}$, we can begin by canceling out the common factors on both sides of the equation.

Notice that both sides share the factors ${(x-3)(x-4)}$. By dividing both sides of the equation by ${(x-3)(x-4)}$, we can simplify it:

$(x-2)(x-3)(x-4) = (x-3)(x-4)(x-5)$ $\frac{(x-2)(x-3)(x-4)}{(x-3)(x-4)} = \frac{(x-3)(x-4)(x-5)}{(x-3)(x-4)}$ $x-2 = x-5$

Now, we can solve for x:

$x - 2 = x - 5$

By subtracting x from both sides:

$-2 = -5$

This equation is not true. Therefore, there is no solution to the original equation ${(x-2)(x-3)(x-4) = (x-3)(x-4)(x-5)}$.