Question

X² - 7x+10. x² + 3x - 10

Answer 1

Ответ:

1)находим корни "х" по Виета

x1=5

x2=2

2)тоже самое, находим корни по Виета

х1=2

х2=-5

Пошаговое объяснение:

либо же можно по Дискриминанту

1)Д=b^2-4*a*c          a=x^2;  b=-7;  c=10

 = 49-40=9

x1= -b+sqrt9/2 =7+3/2=5

x2=-b-sqrt9/2 =7-3/2=2  

2) Д=B^2-4*a*c         a=x^2;  b=3;  c=-10

 =9+40=49

x1=-b+sqrt49/2 = -3+7/2=2

x2=-b-sqrt49/2 =-3-7/2=-5

SQRT- ЭТО КОРЕНЬ КВАДРАТНЫЙ

                         

Answer 2

To solve the system of equations:

1. x² - 7x + 10 = 0
2. x² + 3x - 10 = 0

We can use either factoring, completing the square, or the quadratic formula. Let's use factoring to solve these equations.

1. x² - 7x + 10 = 0: To factor this quadratic equation, we need to find two numbers whose product is 10 (the coefficient of the constant term) and whose sum is -7 (the coefficient of the linear term). The numbers -5 and -2 satisfy these conditions since (-5) * (-2) = 10 and (-5) + (-2) = -7.

So we can rewrite the equation as: (x - 5)(x - 2) = 0

Setting each factor equal to zero, we have: x - 5 = 0 or x - 2 = 0

Solving these equations gives us two solutions: x = 5 or x = 2

2. x² + 3x - 10 = 0: Similarly, to factor this quadratic equation, we need to find two numbers whose product is -10 (the coefficient of the constant term) and whose sum is 3 (the coefficient of the linear term). The numbers 5 and -2 satisfy these conditions since 5 * (-2) = -10 and 5 + (-2) = 3.

So we can rewrite the equation as: (x + 5)(x - 2) = 0

Setting each factor equal to zero, we have: x + 5 = 0 or x - 2 = 0

Solving these equations gives us two solutions: x = -5 or x = 2

Therefore, the solutions to the system of equations are: x = 5, x = 2, x = -5.