Question

(4-2i) +(2-3i)-(1-I)

Answer 1

=4-2i+2-3i-1+l=5-5i+l

Answer 2

To add complex numbers, you simply combine the real parts and the imaginary parts separately.

Given:

(4 - 2i) + (2 - 3i) - (1 - i)

Let's add the real parts and the imaginary parts separately:

Real part: 4 + 2 - 1 = 5

Imaginary part: -2i - 3i + i = -4i

So the result is 5 - 4i.