Question

-3(2,1х + 4 2у)+2,2(-3х- 5у) 7 3 11 22 если х= -1 1, у= 1,2 3

Answer 1

-3(2,1х + 4 2у)+2,2(-3х- 5у)=-6,3х-126у-6,6х-11у=-12,9х-137у=-12,9*(-11)-137*1,2=141,9-164,4=-22,5

если х= -1 1, у= 1,2

7 3 11 22 19 44 41

Answer 2

To evaluate the expression, let's substitute the given values of x and y into the expression:

x = -1, y = 1: -3(2 + 4(2)) + 2.2(-3(-1) - 5(1)) -3(2 + 8) + 2.2(3 - 5) -3(10) + 2.2(-2) -30 + 2.2(-2) -30 + 2(-4.4) -30 - 8.8 -38.8

x = -1, y = 2: -3(2 + 4(2)) + 2.2(-3(-1) - 5(2)) -3(2 + 8) + 2.2(3 + (-10)) -3(10) + 2.2(-7) -30 + 2.2(-7) -30 + 2(-15.4) -30 - 30.8 -60.8

x = 1, y = 1: -3(2 + 4(1)) + 2.2(-3(1) - 5(1)) -3(2 + 4) + 2.2(-3 - 5) -3(6) + 2.2(-8) -18 + 2.2(-8) -18 + 2(-17.6) -18 - 35.2 -53.2

x = 1, y = 2: -3(2 + 4(1)) + 2.2(-3(1) - 5(2)) -3(2 + 4) + 2.2(-3 - 10) -3(6) + 2.2(-13) -18 + 2.2(-13) -18 + 2(-28.6) -18 - 57.2 -75.2

Therefore, the results are: -3(2,1x + 4(2y)) + 2.2(-3x - 5y) = -38.8 when x = -1 and y = 1 -3(2,1x + 4(2y)) + 2.2(-3x - 5y) = -60.8 when x = -1 and y = 2 -3(2,1x + 4(2y)) + 2.2(-3x - 5y) = -53.2 when x = 1 and y = 1 -3(2,1x + 4(2y)) + 2.2(-3x - 5y) = -75.2 when x = 1 and y = 2