Question

B - 2a/( a-b)∙(a^2-b^2)/4a при a=2, b=1

Answer 1

$\frac{b-2a}{ \frac{(a-b)*(a^{2}- b^{2})}{4a}}$, при a=2, b=1 ⇒

$\frac{1-2*2}{ \frac{(2-1)*(2^{2}- 1^{2})}{4*2} }$ = $\frac{1-4}{ \frac{(1)*(4-1)}{8} }$ =  $\frac{-3}{ \frac{1*3}{8} }$  =  $- \frac{3}{ \frac{3}{8} }$ =  $- \frac{1}{ \frac{1}{8} }$ =  $-\frac{1}{8}$

Answer 2

To evaluate the expression B = (2a/(a-b)) * ((a^2-b^2)/(4a)) with a = 2 and b = 1, we substitute the given values into the expression and simplify:

B = (2(2)/(2-1)) * (((2)^2-(1)^2)/(4(2))) = (4/1) * ((4-1)/(8)) = 4 * (3/8) = 12/8 = 3/2

Therefore, when a = 2 and b = 1, the value of B is 3/2.