Question

2tg п/3•ctg(-п/6)+cosп-2sin(п/4)

Answer 1

Если правильно составил уравнение.. то ответ | - радикал
-2*|2/2-1+2tg(п)/3*(-|3)
-1-2|2/2+-2tg(п)|3/3
-1-|2+-2|3*0/3
-1-|2
-2.41

Answer 2

To evaluate the expression 2tg(π/3)•ctg(-π/6) + cos(π) - 2sin(π/4), we'll break it down step by step:

1. Let's start by evaluating the individual trigonometric functions:

   • tg(π/3) = tan(π/3) = √3
   • ctg(-π/6) = cot(-π/6) = 1/√3 (Since cot(x) = 1/tan(x))

2. Substitute the values: 2√3 • 1/√3 + cos(π) - 2sin(π/4)

3. Simplify further: 2 • 1 + cos(π) - 2sin(π/4) 2 + (-1) - 2sin(π/4) 2 - 1 - 2sin(π/4) 1 - 2sin(π/4)

4. Evaluate sin(π/4): sin(π/4) = √2/2

5. Substitute the value: 1 - 2(√2/2) 1 - √2

So, the simplified value of the expression 2tg(π/3)•ctg(-π/6) + cos(π) - 2sin(π/4) is 1 - √2.