Question

14р.37к.+27р.31к.=; 42р.18к+38р.96к=; 38р.46к-12р.25к=; 55р.33к.-19р.68к.=:

Answer 1

14,37+27,31=41,68

42,18+38,96=81,14

38,46-12,25=26,21

55,33-19,68=35,65

Answer 2

To solve these arithmetic problems, let's perform the calculations step by step:

1. 14р.37к. + 27р.31к.:

   • Add the ruble part: 14р + 27р = 41р.
   • Add the kopek part: 37к + 31к = 68к. Therefore, 14р.37к. + 27р.31к. = 41р.68к.

2. 42р.18к + 38р.96к:

   • Add the ruble part: 42р + 38р = 80р.
   • Add the kopek part: 18к + 96к = 114к. Since there are 100 kopeks in 1 ruble, we need to carry over 1 ruble from the kopek part. Therefore, 42р.18к + 38р.96к = 80р.14к.

3. 38р.46к - 12р.25к:

   • Subtract the ruble part: 38р - 12р = 26р.
   • Subtract the kopek part: 46к - 25к = 21к. Therefore, 38р.46к - 12р.25к = 26р.21к.

4. 55р.33к - 19р.68к:

   • Subtract the ruble part: 55р - 19р = 36р.
   • Subtract the kopek part: 33к - 68к. Since the kopek part is smaller than the subtrahend, we need to borrow 1 ruble from the ruble part, making it 35р. We then add 100 kopeks to the minuend and subtract: 133к - 68к = 65к. Therefore, 55р.33к - 19р.68к = 35р.65к.

Therefore, the solutions to the given equations are:

1. 14р.37к. + 27р.31к. = 41р.68к.
2. 42р.18к + 38р.96к = 80р.14к.
3. 38р.46к - 12р.25к = 26р.21к.
4. 55р.33к - 19р.68к = 35р.65к.