
А) 435•17+3008=? б) 435•(17+3008)=? в) 67•64+89•502=? г) 27•(64+89)•502=? задача. MON=75°,
NOA=105°, AOB=75°. Могут ли пары лучей OM и OA, OB быть дополнительными лучами?

Ответы на вопрос




а) To solve the expression 435•17+3008, we can perform the multiplication and addition in order:
435 • 17 = 7395 7395 + 3008 = 10403
Therefore, 435•17+3008 equals 10,403.
б) To solve the expression 435•(17+3008), we need to first calculate the sum inside the parentheses, and then multiply it by 435:
17 + 3008 = 3025 435 • 3025 = 1,316,875
Therefore, 435•(17+3008) equals 1,316,875.
в) To solve the expression 67•64+89•502, we can calculate the multiplication first and then perform the addition:
67 • 64 = 4288 89 • 502 = 44,778 4288 + 44,778 = 49,066
Therefore, 67•64+89•502 equals 49,066.
г) To solve the expression 27•(64+89)•502, we first calculate the sum inside the parentheses, then perform the multiplication, and finally multiply by 502:
64 + 89 = 153 27 • 153 = 4,131 4,131 • 502 = 2,076,462
Therefore, 27•(64+89)•502 equals 2,076,462.
In the problem about the angles, the given angles MON, NOA, and AOB are specified as 75°, 105°, and 75°, respectively.
Two angles are said to be supplementary or complementary if their sum is 180°.
Let's calculate the sum of the angles MON and NOA: 75° + 105° = 180°
Since the sum of MON and NOA is 180°, they can be considered supplementary angles.
Now, let's calculate the sum of the angles MON and AOB: 75° + 75° = 150°
Since the sum of MON and AOB is not 180°, they cannot be considered supplementary angles.
Therefore, the pair of rays OM and OA can be supplementary, but the pair of rays OM and OB cannot be supplementary.


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