Question

Дано: AKMN-ромб АМ=10 см KN=24 см Найти: АК

Answer 1

Ответ: АК=13см

у ромба диагонали перпендикулярны.

пусть диагонали АМ и KN пересекаются в точке О

Рассмотрим треугольник АКО, АК гиппотенуза,КО=KN/2=12см, а АО=АМ/2=5см

т.е. АК=√(КО²+АО²)=√(12²+5²)=√169=13см

Answer 2

Given Information:

We are given that AKMN is a rhombus, AM = 10 cm, and KN = 24 cm. We need to find the length of AK.

Solution:

To find the length of AK, we can use the properties of a rhombus. In a rhombus, all four sides are equal in length.

From the given information, we know that AM = 10 cm. Since AKMN is a rhombus, AK is equal to AM.

Therefore, AK = AM = 10 cm.

So, the length of AK is 10 cm.

Explanation:

In a rhombus, all four sides are equal in length. Since AKMN is a rhombus, AK is equal to AM.

Therefore, AK = AM = 10 cm.