Question

Памогите решить плиз Боковая поверхность цилиндра равна 48п см2, радиус основания - 6 см. Найдите площадь осевого сечение.

Answer 1

S=2ПRh
h=S/2ПR=48П/2П6=4
S=2R*h=4*2*6=48

Answer 2

Calculation of the Lateral Surface Area of a Cylinder

To find the lateral surface area of a cylinder, we need to know the formula for calculating it. The formula for the lateral surface area of a cylinder is given by:

Lateral Surface Area = 2πrh

Where: - π (pi) is a mathematical constant approximately equal to 3.14159. - r is the radius of the base of the cylinder. - h is the height of the cylinder.

In this case, we are given that the lateral surface area of the cylinder is 48π cm² and the radius of the base is 6 cm. We need to find the height of the cylinder.

Let's substitute the given values into the formula and solve for h:

48π = 2π(6)h

Simplifying the equation:

48 = 12h

Dividing both sides of the equation by 12:

h = 4 cm

Therefore, the height of the cylinder is 4 cm.

Calculation of the Area of the Cross-Section

To find the area of the cross-section of the cylinder, we need to know the formula for calculating it. The formula for the area of the cross-section of a cylinder is given by:

Area of Cross-Section = πr²

Where: - π (pi) is a mathematical constant approximately equal to 3.14159. - r is the radius of the base of the cylinder.

In this case, we are given that the radius of the base is 6 cm. Let's substitute this value into the formula and calculate the area of the cross-section:

Area of Cross-Section = π(6)²

Simplifying the equation:

Area of Cross-Section = 36π cm²

Therefore, the area of the cross-section of the cylinder is 36π cm².

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