Question

На высоте равнобедренного треугольника abc проведенная к основанию ac взята точка p на сторонах ab и bc точки m и k соответственно точки m p k не лежат на одной прямой.известно что bm=bk ДОКАЗАТЬ угол bmp и bkp равны угол kmp и pkm равны срочно помогите 7 класс

Answer 1

Тут выкладывают только, первого до четвёртого класса

Answer 2

Task: Proving the equality of angles in a triangle

To prove that angles BMP and BKP are equal, as well as angles KMP and PKM, in a triangle ABC with a point P on sides AB and BC, where BM = BK, we can use the following steps:

1. Draw the triangle ABC with the point P on sides AB and BC. 2. Draw the line segment MP and KP. 3. Since BM = BK, the line segment MP is equal to KP. 4. Now, we need to prove that angles BMP and BKP are equal. 5. To do this, we can use the fact that if two angles are subtended by equal chords on the same side of a circle, then the angles are equal. 6. Let's consider the circle passing through points B, M, and K. 7. Since BM = BK, the chords MP and KP are equal. 8. Therefore, angles BMP and BKP are equal. 9. Similarly, we can prove that angles KMP and PKM are equal by considering the circle passing through points K, M, and P. 10. Thus, we have proved that angles BMP and BKP are equal, as well as angles KMP and PKM.

Please note that the proof provided above is a general approach based on the given information. If you need a more specific proof or have any additional questions, feel free to ask!