Question

плоскость а пересекает шар на растоянии8см от его центра. радиус равен 10см ..найдите радиус куруга.полученного сечения

Answer 1

очевидно, что он будет равен корню квадратного из десять в квадрате минут восемь в квадрате, т.е. 6 см

Answer 2

Finding the Radius of the Circle Obtained from the Intersection of a Plane and a Sphere

To find the radius of the circle obtained from the intersection of a plane and a sphere, we need to use the given information.

The plane intersects the sphere at a distance of 8 cm from its center, and the radius of the sphere is 10 cm.

Let's denote the radius of the circle obtained from the intersection as r.

To find r, we can use the Pythagorean theorem. The distance from the center of the sphere to the point where the plane intersects the sphere is the hypotenuse of a right triangle, with one leg being the radius of the sphere and the other leg being the radius of the circle.

Using the Pythagorean theorem, we have:

r^2 + 8^2 = 10^2

Simplifying the equation, we get:

r^2 + 64 = 100

Subtracting 64 from both sides, we have:

r^2 = 36

Taking the square root of both sides, we get:

r = 6

Therefore, the radius of the circle obtained from the intersection of the plane and the sphere is 6 cm.