Question

Дан равнобедренный треугольник АВС, у которого боковая сторона равна 12см, а основание равно 10см. Найти периметр треугольника, образованного средними линиями.

Answer 1

Ответ:

Р=12+12+10=34

Вот мой ответ

Answer 2

Perimeter of a Triangle formed by the Midsegments

To find the perimeter of a triangle formed by the midsegments of a given isosceles triangle ABC, we need to determine the lengths of the midsegments.

Given: - Side AB = 12 cm (the leg of the isosceles triangle) - Base AC = 10 cm (the base of the isosceles triangle)

To find the length of the midsegment, we can use the following formula:

Length of Midsegment = (1/2) * (Length of Base)

Using this formula, we can calculate the length of the midsegment:

Length of Midsegment = (1/2) * 10 cm = 5 cm

Now that we have the length of the midsegment, we can find the perimeter of the triangle formed by the midsegments.

The triangle formed by the midsegments of an isosceles triangle is also an isosceles triangle. In this case, the midsegment triangle is also an isosceles triangle with two equal sides, each equal to the length of the midsegment.

To find the perimeter of the triangle formed by the midsegments, we can use the following formula:

Perimeter = 2 * (Length of Midsegment) + Length of Base

Substituting the values we have:

Perimeter = 2 * 5 cm + 10 cm = 10 cm + 10 cm = 20 cm

Therefore, the perimeter of the triangle formed by the midsegments is 20 cm.

Please let me know if you need any further assistance!